Example: MN Blood Group

• In a population of 100 individuals:

  • 36 are MM, 48 are MN, 16 are NN.

• # of M alleles = 2(36) + 48 = 120

  • 120/200=0.6 or 60%

• The # of N alleles = 48 + 2(16) = 80

  • 80/200=0.4 or 40%

Previous slide

Next slide

Back to first slide

View graphic version