Heteropolymers: Ratios of 2 bases
3A = AAA = (1/6)3X100 = 0.4% = Lysine
2A:1C = AAC,ACA,CAA = (2.3%) X 3 = 6.9% = Asparagine
(1/6)2X(5/6)X100 Glutamine
1A:2C = ACC,CAC,CCA = (11.6) X3 = 34.8% = Threonine
(1/6)X(5/6)2X100 Histidine
3C = CCC = (5/6)3 X100 = 57.9% = Proline
Therefore: a protein translated from a DNA made from 1A and 5C should be 0.4% Lysine, 6.9% Asparagine and Glutamine, 34.8% Threonine and Histidine, and 57.9% Proline